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Passenger Family Survival Analysis
Extract each passenger's last name (before the comma) and group potential family members. For last names shared by 2 or more passengers, show: last_name, family_size, survivors, survival_rate (1 dec). Sort by family_size descending. This reveals whether families survived together.
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Schema
passengers
| passenger_id | survived | pclass | name | sex | age | sibsp | parch | fare | embarked |
|---|---|---|---|---|---|---|---|---|---|
| 1 | 0 | 3 | Braund, Mr. Owen Harris | male | 22 | 1 | 0 | 7.25 | S |
| 2 | 1 | 1 | Cumings, Mrs. John Bradley | female | 38 | 1 | 0 | 71.28 | C |
| 3 | 1 | 3 | Heikkinen, Miss. Laina | female | 26 | 0 | 0 | 7.93 | S |
Expected output: Braund | 2 | 1 | 50.0
Hint
Concepts
SELECT String Functions GROUP BY HAVING Aggregation
Practise the topic: SQL practice questions · String function practice · GROUP BY exercises · Advanced SQL interview questions
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